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7 votes
7 votes
X^2+3x-18 use factoring to determine the zeros

User Kamaros
by
2.9k points

1 Answer

22 votes
22 votes

Answer:

x = 3
x = -6

Explanation:

Hello!

Let's first set the equation to 0.

  • x² + 3x - 18 = 0

To factor, first think about two numbers that multiply to -18, but add up to 3. The two numbers are 6 and -3.

Now, expand 3x to 6x and -3x. Then, factor by grouping.

Factor

  • x² + 3x - 18 = 0
  • x² + 6x - 3x - 18 = 0
  • (x² + 6x) - (3x + 18) = 0
  • x(x + 6) -1(3)(x + 6) = 0
  • (x - 3)(x + 6) = 0

Now, set each factor to 0 and solve for x

Solve

  1. (x - 3) = 0
    x = 3
  2. (x + 6) = 0
    x = -6

x = 3, x = -6

User Cave Johnson
by
3.3k points