Question

Im hvaing a hard time getting the right answer

1. If 2.49 g of CuNO3 is dissolved in water to make a 0.830 M solution, what is the volume of the solution in milliliters?

.01599 and 15.99 is wrong and I think Im doing the equation wrong, help!

Answer 1

`V=23.9mL`

Step-by-step explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

`n=2.49g*(1mol)/(125.55 g)=0.0198mol`

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

`M=(n)/(V)\\\\V=(n)/(M)`

By plugging in the moles and molarity, we obtain:

`V=(0.0198mol)/(0.830mol/L)=0.0239L`

Which in mL is:

`V=0.0239L*(1000mL)/(1L)\\\\V=23.9mL`

Best regards!