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What is 5[cos(Pi/4) + I sin (pi/4)] raised to the 3rd power?

User Twoam
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2 Answers

4 votes

Final answer:

To solve 5[cos(π/4) + i sin (π/4)]^3, we utilize De Moivre's Theorem to get (-√2/2 + i√2/2)^3. After evaluation, we adjust for the coefficient by multiplying by 5^3, leading to the final answer of -62.5 - 62.5i.

Step-by-step explanation:

The expression given is 5[cos(π/4) + i sin (π/4)] raised to the 3rd power. To solve this, we can use De Moivre's Theorem which states that (cos θ + i sin θ)^n = cos(nθ) + i sin(nθ). For our case, θ = π/4 and n = 3, so we can evaluate the expression as follows:

  1. Multiply the angle by 3: π/4 * 3 = 3π/4.
  2. Find the cosine and sine of 3π/4: cos(3π/4) = -√2/2 and sin(3π/4) = √2/2.
  3. Apply the theorem: (cos(3π/4) + i sin(3π/4))^3 = (-√2/2 + i√2/2)^3.
  4. Since the original expression has a coefficient of 5, we multiply the result by 5^3.

Therefore, the final evaluated expression is -125(1/2 + i/2), which simplifies to -62.5 - 62.5i.

User Harvinder
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7 votes

Answer: The answer is C on edge

Step-by-step explanation:

User Sebastian Juarez
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