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If AC = 41, find the value of x? (Giving 35 points) ​
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If AC = 41, find the value of x? (Giving 35 points) ​

If AC = 41, find the value of x? (Giving 35 points) ​-example-1
User Ranjith Siji
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17 votes


\huge \boxed{\sf x=2}\\\\\\\displaystyle \sf AC=AB+BC\\\\41=3x-1+14x+8\\\\41=17x+7\\\\Subtracting\ 7\ from\ each\ side \\\\ 41-7=17x+7-7 \\\\ 34=17x\\\\Dividing\ each\ side\ by\ 17 \\\\ (34)/(17)=(17x)/(17) \\\\ 2=x

User Visakh
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2.7k points
11 votes
11 votes
3x-1 + 14x+8= 41
17x+7= 41
17x = 34
X = 2
User Bgaze
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3.3k points
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