If AC = 41, find the value of x? (Giving 35 points)

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Jul 26, 2023 156k views

12 votes

If AC = 41, find the value of x? (Giving 35 points)

Mathematics
high-school

Trevor De Koekkoek asked

by Trevor De Koekkoek

7.8k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

5 votes

$\huge \boxed{\sf x=2}\\\\\\\displaystyle \sf AC=AB+BC\\\\41=3x-1+14x+8\\\\41=17x+7\\\\Subtracting\ 7\ from\ each\ side \\\\ 41-7=17x+7-7 \\\\ 34=17x\\\\Dividing\ each\ side\ by\ 17 \\\\ (34)/(17)=(17x)/(17) \\\\ 2=x$

Thomas Francois answered Jul 28, 2023

by Thomas Francois

7.9k points

0 Comments

Please log in or register to add a comment.

4 votes

3x-1 + 14x+8= 41
17x+7= 41
17x = 34
X = 2

Bill Patterson answered Jul 30, 2023

by Bill Patterson

8.2k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.0m questions

11.7m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions