If AC = 41, find the value of x? (Giving 35 points)

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asked Jul 26, 2023 156k views

12 votes

If AC = 41, find the value of x? (Giving 35 points)

Mathematics
high-school

Trevor De Koekkoek asked

by Trevor De Koekkoek

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2 Answers

5 votes

$\huge \boxed{\sf x=2}\\\\\\\displaystyle \sf AC=AB+BC\\\\41=3x-1+14x+8\\\\41=17x+7\\\\Subtracting\ 7\ from\ each\ side \\\\ 41-7=17x+7-7 \\\\ 34=17x\\\\Dividing\ each\ side\ by\ 17 \\\\ (34)/(17)=(17x)/(17) \\\\ 2=x$

Thomas Francois answered Jul 28, 2023

by Thomas Francois

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4 votes

3x-1 + 14x+8= 41
17x+7= 41
17x = 34
X = 2

Bill Patterson answered Jul 30, 2023

by Bill Patterson

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