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The point-slope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1=1/4(x-12). What is the standard form of the equation for this line? x - 4y = 8 O x - 4y=2 4% - y = 8 O 49
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The point-slope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1=1/4(x-12). What is

the standard form of the equation for this line?
x - 4y = 8
O x - 4y=2
4% - y = 8
O 49 - y = 2

User Frank Luke
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1 Answer

3 votes

Answer:

The answer is: x-4y=8

User Kirkaracha
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