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How many atoms are present in 1.4 grams of aluminum?

1 Answer

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Answer: 3.2x10^23

Step-by-step explanation:

Start by finding the molar mass of aluminum.

Then turn grams into moles by dividing grams of substance by molar mass. 1.4g÷26.98g

Then multiply that by 6.022x10^23 atoms. 0.0519x6.022x10^23

You can use dimensional analysis to solve this type of problem.

User ShaunUK
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