Question

HELP ME PLEASE I NEED HELP

Answer 1

a.)
`x=12`

b.)
`A=50`

Explanation:

a.) Remember: the sum of all angles in a triangle will always be 180°.

Make an equation in which all given angles add up to 180:

∠1+∠2+∠3=180

`(3x+14)+(7x-4)+50=180`

Solve the equation for the value of x. Remove the parentheses:

`3x+14+7x-4+50=180`

Combine like terms:

`(3x+7x)+(14-4+50)=180\\\\10x+60=180`

Subtract 60 from both sides:

`10x+60-60=180-60\\\\10x=120`

Divide both sides by 10:

`(10x)/(10)=(120)/(10) \\\\x=12`

The value of x is 12.

b.) Insert the value of x into the given value of ∠A:

`A=3x+14\\\\A=3(12)+14`

Simplify multiplication:

`A=36+14`

Add:

`A=50`

∠A is 50°.

:Done

Check Your Work:

To make sure the given values are true, solve for ∠B:

`B=7(12)-4\\\\B=84-4\\\\B=80`

Now add all angle values to determine if they add up to 180°:

`50+50+80=180\\\\100+80=180\\\\180=180`

Since 180 is equal to 180, the values are true.

Answer 2

50°

Explanation:

50 + (3x + 14) + (7x - 4) = 180

50 + 3x + 14 + 7x - 4 = 180

60 + 10x = 180

10x = 180 - 60

10x = 120

x = 120/10

x = 12

So, Angle A is:

(3 * 12) + 14

36 + 14 = 50°