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Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A) 28 + 65H ≤ 250

B)28 + 65H ≥ 250

C) 65 + 28H ≤ 250

D) 65 + 28H ≥ 250

2) What is the largest whole number of hours that Anand can afford?

hours

User Matleg
by
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2 Answers

6 votes

Answer

1.) B

2.) 3 hours

Explanation:

1.) option B is correct I think because it shows he will either be equal to or less than how much money he wants to spend

2.) i got three because if you sent up the equal I picked in question one then you subtract 28 from 250 giving u 222 and you divide that by 65 giving you 3.4 but he only charges by the whole hour so that .4 of an hour he wouldn't charge you for

User Shredding
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5.9k points
1 vote

1 The inequality that describes this scenario is C) 65 + 28H ≤ 250

2 Anand can afford a maximum of 6 hours of work from the plumber.

1 The inequality describing the scenario is:

"65 + 28H ≤ 250."

So, the correct answer is: "C) 65 + 28H ≤ 250."

2 To find the largest whole number of hours Anand can afford:

"65 + 28H ≤ 250."

Subtract 65 from both sides:

"28H ≤ 185."

Divide by 28 (since H is a whole number):

"H ≤ 6 with a remainder of 17."

The largest whole number that satisfies this inequality is H = 6.

So, Anand can afford a maximum of 6 hours of work from the plumber.

User Peter Drier
by
6.5k points