1 The inequality that describes this scenario is C) 65 + 28H ≤ 250
2 Anand can afford a maximum of 6 hours of work from the plumber.
1 The inequality describing the scenario is:
"65 + 28H ≤ 250."
So, the correct answer is: "C) 65 + 28H ≤ 250."
2 To find the largest whole number of hours Anand can afford:
"65 + 28H ≤ 250."
Subtract 65 from both sides:
"28H ≤ 185."
Divide by 28 (since H is a whole number):
"H ≤ 6 with a remainder of 17."
The largest whole number that satisfies this inequality is H = 6.
So, Anand can afford a maximum of 6 hours of work from the plumber.