Answer:
Hey, you have to solve it by Stichiometry.....answer is option A.... I have explained every option for your understanding.
Step-by-step explanation:
(a.)**For option A, the volume of CO2 produced at STP will be 5.6 not 30.8 by solving equation for part I
By Stichiometry,
moles of CO2, n=11.2/22.4 = 0.5
Volume of CO2, V=11.2×0.5 =5.6
(b.)**For option B, the statement is correct
n(moles) of O2 =32/32 = 1 mol
we have to use stichiometry to find moles of CO2
n= 1/2 × 1 (coefficient of CO2/coefficient of O2) × mol of O2 (coz O2 is limiting reagent in 2nd option)
n= 0.5 mol
Mass= n × Molecular Mass
Mass= 0.5 × 44
Mass= 22g
(c.)**option C, is correct acc. to statement
(d.)**option D, is correct acc. to statement
(e.)**option E, is correct acc. to statement
Answer to this question is A part.
Hope it helps......