Answer:
Width = 4 in
Length = 8 in
Explanation:
Given:
Area of a rectangle = 32 in²
Find:
Length and width
Computation:
Assume;
Width = x
Length = x + 4
Area of a rectangle = lb
32 = (x+4)(x)
x² + 4x = 32
x² + 4x - 32 = 0
x² + 8x - 4x - 32 = 0
x(x+8) - 4(x+8) = 0
(x-4)(x+8)
x = 4 , x = -8
So,
Width = x = 4 in
Length = x + 4 = 4 + 4 = 8 in