Answer:
30.128 days
Step-by-step explanation:
Given that:
Mean = 25
Standard deviation = 4
Confidence interval = 90% = 0.9
Since the confidence interval should not exceed 90%
Then using z test table
P(z) = 0.9
For 0.8997 , we get = 1.28
For 0.9015, we get = 1.29
∴
![(0.9 - 0.8897)/(0.9015 - 0.8997 )=( z - 1.28)/(1.29 -1.28)](https://img.qammunity.org/2021/formulas/engineering/college/zdrwy4k6gmmg457hbxlq12se2eb16ggkqr.png)
By solving
Z = 1.282
Thus, the duration to be used so that it will not exceed 90% C.I is:
Z = (x - μ)/σ
1.282= ( x - 25)/4
1.282 * 4 = x - 25
(1.282*4)+25 = x
x = 30.128 days