Question

C.
If 150 grams of oxygen are produced, how many moles of sodium chlorate decomposed

Answer 1

3.13 moles of sodium chlorate are decomposed.

Step-by-step explanation:

Given data:

Mass of oxygen produced = 150 g

Number of moles of sodium chlorate decomposed = ?

Solution:

Chemical equation:

2NaClO₃ → 2NaCl + 3O₂

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 150 g/ 32 g/mol

Number of moles = 4.7 mol

Now we will compare the moles of oxygen with sodium chlorate.

O₂ : NaClO₃

3 : 2

4.7 : 2/3×4.7 = 3.13 mol

3.13 moles of sodium chlorate are decomposed.