Question

Q 1. Element M is a metal that forms compounds of the type MX2, MX3, and MX4, where X is a Chlorine (Cl).

I) What is the expected trend in the ionic radius of M in these compounds?
II) Arrange these compounds in order of decreasing ionic radius of M.

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Answer 1

dont know

Step-by-step explanation:

Answer 2

See explanation

Step-by-step explanation:

The ionic radius of metal M decreases as the magnitude of charge on the metal M increases. The ionic radius is the distance between the nucleus and the electron in the outermost shell of an ion. So, ionic radius decreases with increasing positive charge.

We can see that from the various formulae in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;

MX2 > MX3 > MX4