Question

300cm³ of hydrogen diffuses through a porous pot in 50 seconds how long will it take 500 cm cube of oxygen diffuses through the same pot(h=1,o=16)​

Answer 1

It takes 333.3 s for Oxygen to diffuses

Further explanation

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or

the effusion rates of two gases = the square root of the inverse of their molar masses:

`\rm (r_1)/(r_2)=\sqrt{(M_2)/(M_1) }`

or

`\rm M_1* r_1^2=M_2* r_2^2`

r₁ H₂ = 300 cm³/50 s=6 cm³/s

M₁ H₂ = 2 g/mol

M₂ O₂ = 32 g/mol

`\tt 2* 6^2=32* r_2^2\\\\r_2^2=(2* 6^2)/(32)=2.25\rightarrow r_2=1.5`

the diffusion time of Oxygen :

`\tt r_2=(V)/(t)\\\\t=(V)/(r_2)=(500~cm^3)/(1.5~cm^3/s)=333.3~s`