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consider f(x) = x^3 + x^1 would the function be even, odd, neither,or not enough information to determine

User Zaur
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1 Answer

1 vote

Answer:

The function is odd

Explanation:

Even functions and odd functions are those which satisfy particular symmetry relations as follows:

f(x) is even if f(-x) = f(x)

f(x) is odd if f(-x) = -f(x)

Not all functions are eligible for being even or odd.

Considering


f(x)=x^3+x^1

Let's find f(-x)


f(-x)=(-x)^3+(-x)^1

Since
(-x)^3=(-x)(-x)(-x)=-x^3

And
(-x)^1=-x:


f(-x)=-(x)^3-(x)^1

Factoring by -1:


f(-x)=-((x)^3+(x)^1)

The expression in parentheses if f(x), thus:


f(-x)=-f(x)

And the function is odd.

User Mahdi Pishguy
by
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