Question

At Joe's Pizzeria, small pizzas cost $7.50, and large pizzas cost

$11.00. One day between 3:00 PM and 9:00 PM, Joe sold 100 pizzas
and took in $848. How many more small pizzas than large pizzas did
Joe sell during that 6-hour period?
(A) 28
(B) 44
(C) 56
(D) 72

Answer 1

Joe sold 44 more small pizzas than large pizzas during that 6-hour period.

Step-by-step explanation:

To find the number of small pizzas and large pizzas sold, we can solve a system of equations. Let x be the number of small pizzas and y be the number of large pizzas. We can set up the following equations:

x + y = 100

7.50x + 11.00y = 848

Using substitution or elimination method, we can solve for x and y. Solving this system of equations, we find that x = 44 and y = 56. Therefore, Joe sold 44 more small pizzas than large pizzas during that 6-hour period.

Answer 2

Option B. 44 is the correct answer

Step-by-step explanation:

Let l be the number of large pizzas and s be the number of small pizzas

Then according to the given statement the equations will be:

`l+s = 100\ \ \ Eqn\ 1\\11l+7.5s = 848\ \ \ Eqn\ 2`

From equation 1

`l = 100-s`

Putting in equation 2

`11(100-s)+7.5s = 848\\1100-11s+7.5s = 848\\-3.5s+1100 = 848\\-3.5s = 848-1100\\-3.5s = -252\\(-3.5s)/(-3.5) = (-252)/(-3.5)\\s = 72`

Putting s=72 in equation 1

`l+72 = 100\\l = 100-72\\l = 28`

How many more small pizzas means we have to find s-l

So,

s-l = 72-28 = 44

Hence,

Option B. 44 is the correct answer