Answer:
1.16 k/ft
Step-by-step explanation:
From the given information;
Using table 1.3 for Minimum design dead loads;
For 12-in clay brick,
the obtained min. design dead load = 115 psf
For Fiberboard 1/2 in. ceilings, the minimum design dead load is 0.75 psf
To start with the load that is being exerted on the floor as a result of the clay brick wall (
), we have:
![L_1 = Load * h](https://img.qammunity.org/2021/formulas/engineering/college/r1jtkv8fz08nl2rftk0za4ti97xoe0t5w7.png)
![L_1 = 115 * 10](https://img.qammunity.org/2021/formulas/engineering/college/hgmwqpptws94rd7onufups6nns3csk8s4o.png)
![L_1 = 1150 \ lb/ft](https://img.qammunity.org/2021/formulas/engineering/college/6paqhsl8r1dpbh57fmwf5252enc163us98.png)
To calculate the load exerted on the floor as a result of the 1/2 fireboard, we have:
![L_2 = Load * h](https://img.qammunity.org/2021/formulas/engineering/college/1xp41q6uuvf7gt9jwhonxlsiv8i7m8rpzq.png)
![L_2 = 0.75 * 10](https://img.qammunity.org/2021/formulas/engineering/college/6h465i08takcjqa6kslj2zjba9m2p5c0oz.png)
![L_2 = 7.5 \ lb/ft](https://img.qammunity.org/2021/formulas/engineering/college/tnd0gqcuo3luvxsizckcmisrl5wxxggfhl.png)
The total load exerted on the floor =
![L_1 + L_2](https://img.qammunity.org/2021/formulas/engineering/college/tqvqo5o0b8nsh3fp21lsd97vrzfqxvzhjm.png)
The total load exerted on the floor = 1150 + 7.50
The total load exerted on the floor = 1157.50 lb/ft
To (k/ft), we get:
![= 1157.50 \ lb/ft * (1 \ k)/(1000 \ lb)](https://img.qammunity.org/2021/formulas/engineering/college/dfb0ly4pj4xxxg8g935y9d7qgyssw1eo9x.png)
= 1.157 k/ft
≅ 1.16 k/ft