Question

Consider a circuit element, with terminals a and b, that has vab= -12V and iab= 3A. Over a period of 2 seconds, how much charge moves through the element? If electrons carry the charge, which terminal do they enter? How much energy is transferred? Is it delivered to the element or taken from it?

Answer 1

a) 6 coulombs

b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current

c) = -72 joules

Energy is taken from element

Step-by-step explanation:

Given data:

V ab = -12 v

I ab = 3A

period ( t ) = 2 seconds

a) determine how much charge moves through the element

q = I * t

= 3 * 2 = 6 coulombs

b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current

c) determine how much energy is transferred

= Vab * Iab * t

= -12 * 3 * 2

= -72 joules

Energy is taken from element