Answer:
The range of the projectile is 60 m
Step-by-step explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
![v_x=v_o](https://img.qammunity.org/2021/formulas/physics/college/rpf37o6wmvy6ghiquguh3zch7e5qjic5oj.png)
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
![v_y=g.t](https://img.qammunity.org/2021/formulas/physics/college/6nlivco1hucwq5n5si5h5wlthg4cz6gkfw.png)
The horizontal distance is calculated as a constant speed motion:
![x = v_x.t](https://img.qammunity.org/2021/formulas/physics/college/vhoo02upvdxb56w60k3g1u8e2fnsc7teu1.png)
Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:
x = 15*4 = 60
The range of the projectile is 60 m