Answer:
![S.A.=90\pi~cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/yynvqkrtsfmaf2lhr5z3n0pvw8dmpsqarq.png)
Explanation:
Surface Area of a Cone
Given a cone of base area B and slant height L, the surface area can be calculated with the formula:
![S.A.=\pi rL +B](https://img.qammunity.org/2021/formulas/mathematics/high-school/vo16w32nbtvm4clzqjp2jvl1ivavf5dfhn.png)
The cone presented in the image has a circular base of radius r=5 cm, thus its base area is:
![B=\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/kbbf8033ekecsycvwximxm29cpw58nubdp.png)
![B=\pi 5^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/va8bsamr5f84zhfshuu2r4hhebk81tjjy7.png)
![B=25\pi~cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/88d6cgr5y1kbszfkxy1nq2xj5qwkxdo6lc.png)
The slant height can be calculated as the hypotenuse of a right triangle with legs 5 cm and 12 cm by using Pythatgora's Theorem:
![L^2=5^2+12^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/iyhfkpqfrf09nab96t2ewvc22hl8c4qc61.png)
![L^2=25+144=169](https://img.qammunity.org/2021/formulas/mathematics/high-school/ijimpagkp6au75epzvwguk0z0xdc2m5tm5.png)
Taking square roots
![L = √(169)](https://img.qammunity.org/2021/formulas/mathematics/high-school/87fxv77eihololvb2cpyn2sf9lub3yo2wn.png)
L = 13 cm
The surface area is:
![S.A.=\pi (5~cm)*13~cm +25\pi~cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/wtjcypjvtityp42gd5pacpgxich7cn86ot.png)
Operating:
![S.A.=65\pi~cm^2 +25\pi~cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/btipq2pcgb648mu8738nntadmdvwjonxfw.png)
![\mathbf{S.A.=90\pi~cm^2}](https://img.qammunity.org/2021/formulas/mathematics/high-school/g5iebh2dopcjkq80w0i5dwnka5s68idmqo.png)