Question

a truck of mass 150kg is released from rest at point A and moves along a frictionless truck as shown below​

Answer 1

Vmax = 34.3[m/s]

Step-by-step explanation:

We must remember that the definition of energy transformation, which tells us that potential energy is transformed into kinetic energy and vice versa.

Potential energy is defined as the product of mass by gravity by height.

`E_(p)=m*g*h`

where:

m = mass = 150 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 60 [m]

`E_(p)=150*9.81*60\\E_(p)=88290 [J]`

When the height is zero, all the potential energy will have been transformed into kinetic energy, with this kinetic energy we can calculate the velocity.

`E_(k)=(1)/(2) *m*v^(2)\\E_(k)=(1)/(2)*150*v^(2)\\88290=0.5*150*v^(2)\\v=\sqrt{(88290)/(0.5*150) }\\v=34.3[m/s]`

The maximum kinetic energy is reached in B