Answer:
![\displaystyle S_(27)=675](https://img.qammunity.org/2021/formulas/mathematics/high-school/qf2kzd23knxkis7qaie2u24mj5co781y6w.png)
Explanation:
The sum of N consecutive natural numbers is given by:
![\displaystyle S_N=(N)/(2)(F+L)](https://img.qammunity.org/2021/formulas/mathematics/high-school/h6547yl92vkejn0lqc74rk4tfo982dzsip.png)
We need to find the sum of the natural numbers between 12 to 38.
To calculate the required sum we have F=12, L=38, but we don't have the value of N.
From 12 to 38 there are 38 - 12 + 1 = 27 natural consecutive numbers, thus N=27.
Substituting in the formula:
![\displaystyle S_(27)=(27)/(2)(12+38)](https://img.qammunity.org/2021/formulas/mathematics/high-school/eue1dckzojcv1lph92fvjglaf423dmwzx1.png)
![\displaystyle S_(27)=(27)/(2)(50)](https://img.qammunity.org/2021/formulas/mathematics/high-school/49hoaut22ccr3ypednv9dx4mzrfwtojuxf.png)
![\displaystyle S_(27)=27*25](https://img.qammunity.org/2021/formulas/mathematics/high-school/yiyv8zn78hy76nzrpy4evshgcatfxgizhn.png)
![\mathbf{\displaystyle S_(27)=675}](https://img.qammunity.org/2021/formulas/mathematics/high-school/4tevvnh6titysq6243pzr90itufor43ja2.png)