Question

Assume all vars are positive reals​

Answer 1

`\frac{x^(3)\sqrt[3]{x} }{4}`

Explanation:

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What this is saying is it is taking the cubed root (which is like a square root, except it is using a 3 instead of 2) of x to the power of 10 divided by 64.

The equation is also saying:

`\frac{\sqrt[3]{x^(10) }}{\sqrt[3]{64} }`

We can simplify the bottom half of the fraction to be 4. The cube root of something is essentially saying its the number times itself 3 times (in this case, divided by that original number). The number to get to 64 was 4 and it was done like this: 4 times 4 times 4 (which equals 64).

As for the top equation, it will simplify down to
`x^(3) \sqrt[3]{x}`.

Since
`x^(10)` can be broken up to be x and
`x^(9)`, we cube root the
`x^(9)` to become
`x^(3)`, while the x remains the same.

We come to result of
`\frac{x^(3)\sqrt[3]{x} }{4}`, which is the answer.

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