Question

The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the solution?

Answer 1

0.805 M.

Step-by-step explanation:

Hello!

In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

`n=15.0gKCl*(1molKCl)/(74.55gKCl)=0.201molKCl`

Next, since the volume is 0.2500 in liters, the molarity turns out:

`M=(0.201mol)/(0.2500L) \\\\M=0.805M`

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