Hi there! :)
A line that is parallel to y = 2x + 3 must have the same slope of 2. Therefore:
We can use the given point as well as the slope-intercept formula y = mx + b to solve.
Plug in the x-coordinate for "x" and y-coordinate of the point into "y":
2 = 2(-2) + b
2 = -4 + b
6 = b
Rewrite the equation:
y = 2x + 6