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Write the equation of the line passing through the point (-2, 2) that is parallel to the line y = 2x + 3

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Hi there! :)


\large\boxed{y = 2x + 6}

A line that is parallel to y = 2x + 3 must have the same slope of 2. Therefore:

We can use the given point as well as the slope-intercept formula y = mx + b to solve.

Plug in the x-coordinate for "x" and y-coordinate of the point into "y":

2 = 2(-2) + b

2 = -4 + b

6 = b

Rewrite the equation:

y = 2x + 6

User Denchr
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