Question

How many liters are there in 144g of H₂O (g)?
What is the mass of 200L at STP of H₂O₂ (g)?

Answer 1

1. 179.2 L

2. 303.62 g

Step-by-step explanation:

1. Determination of volume of H₂O (g).

We'll begin by calculating the number of mole in 144 g of H₂O. This is illustrated below:

Mass of H₂O = 144 g

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mole of H₂O =?

Mole = mass /Molar mass

Mole of H₂O = 144/18

Mole of H₂O = 8 moles

Finally, we shall determine volume of H₂O (g) as follow:

1 mole of any gas occupy 22.4L at stp.

Therefore, 8 moles of H₂O (g) will occupy =

8 × 22.4 = 179.2 L

Thus, 144 g of H₂O (g) occupies 179.2 L

2. Determination of the mass of H₂O₂ (g).

We'll begin by calculating the number of mole of H₂O₂ (g) that occupied 200 L at STP. this can be obtained as follow:

1 mole of any gas occupy 22.4 L at stp.

Therefore, Xmol of H₂O₂ (g) will occupy 200 L at STP i.e

Xmol of H₂O₂ (g) = 200/22.4

Xmol of H₂O₂ (g) = 8.93 moles

Thus, 8.93 moles of H₂O₂ (g) occupied 200 L at STP.

Finally, we shall determine the mass of H₂O₂ (g) as follow:

Mole of H₂O₂ (g) = 8.93 moles

Molar mass of H₂O₂ = (2×1) + (2×16) = 2 + 32 = 34 g/mol

Mass of H₂O₂ =?

Mole = mass /Molar mass

8.93 = mass of H₂O₂ /34

Cross multiply

Mass of H₂O₂ = 8.93 × 34

Mass of H₂O₂ = 303.62 g