Question

Can someone help me with this?-- 15 pts!

2H2 + O2 → 2H2O

At the beginning of the reaction, it is measured that there are 15.0 g of hydrogen (H2) and 97.0 g of oxygen (O2).

What is the theoretical yield for the water that will be produced in the reaction? (M H2O = 18.0 g/mol; M CH4 = 16.0 g/mol)

2.73 x 101 g H2O
1.34 x 102 g H2O
1.08 x 102 g H2O
5.38 x 100 g H2O

Answer 1

1.08 x 10^2 gm of H2O

Step-by-step explanation:

number of moles of O2 = 97g /32 g/moles = 3.03 moles

3.03 moles of O2 produces 6.06 moles of H2O

amount of water produced = 6.06 mol x 18 g /mol = 109.08 g = 1.08 x 10^2 g