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What is the vertex of the parabola with the equation y=1/5x^2 + 2x - 8

What is the vertex of the parabola with the equation y=1/5x^2 + 2x - 8-example-1
User Shak Ham
by
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1 Answer

2 votes

Answer:

(-5,-13)

Explanation:

Find the vertex of the parabola y=1/5x^2+2x−8.

In this equation a=15 and b = 2.

x= -2/2(1/5) = -2/2/5 = -2/1 * 5/2 = -5

Substitute −5 into the equation y=1/5x^2+2x−8

y=1/5(−5)^2+2(−5)−8

y=5−10−8

y=−13

The vertex is (−5 , −13)

User Kamal Kumar
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