Question

Write the equation of a line passing through the given point that is

perpendicular to the given line. 3.x – 8y = 16; (-3, 1)

Answer 1

-8x-21=3y or -8/3x-7=y or 8x+y+21=0

Explanation:

First find the slope of 3x-8y=16.

3x-16=8y (divide both sides by 8 so that y is isolated)

3/8x-2=y The slope is 3/8. The perpendicular slope is the negative reciprocal of 3/8, which is -8/3

Using the points, the equation of the line can be found.

(-8/3=y-1/x-(-3))3(x-(-3) (3(x-(-3) is the common denominator

This equals -8x-24=3y-3, add three to both sides which equals -8x-21=y.

The other answers are written in slope y-intercept form and general form.

*Note: x-(-3) can be written as x+3