Question

Find the enthalpy for a constant pressure calorimetry reaction where the reaction occurs in a 250ml aqueous solution. The temperature changes from 25.0c to 26.1 c

Assume that cool = 4.18j/gt

Answer 1

`\Delta H=1149.5J`

Step-by-step explanation:

Hello!

In this case, since the calorimeter contains a solution for which the specific heat is 4.18 J/g°C, which is equal to that of the water, we can also notice that the density is 1.00 g/mL and therefore the present mass is 250 g. In such a way, we compute the enthalpy change as shown below:

`\Delta H=mC\Delta T`

Thus, by plugging in the mass, specific heat and temperature change, we obtain:

`\Delta H=250g*4.18(J)/(g\°C)(26.1\°C-25.0\°C)\\\\\Delta H=1149.5J`

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