Question

A force of 1.50 N acts on a 0.20kg trolley so as to accelerate it along an air track

The track and force are horizontal and in line . How fast is the trolley going after acceleration from rest through 30cm , if friction is negligible​

Answer 1

2.12m/s

Step-by-step explanation:

Given parameters:

Force on trolley = 1.5N

Mass of trolley = 0.2kg

Unknown:

Velocity of the trolley = ?

Solution:

To solve this problem, we first find the acceleration of the trolley;

Force = mass x acceleration

Acceleration =
`(Force )/(mass)`

Insert the parameters and solve;

Acceleration =
`(1.5)/(0.2)` = 7.5m/s²

Now to find the acceleration;

Initial velocity = 0m/s

v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

Distance = 30cm and this is 0.3m

v² = 0² + 2(7.5)0.3 = 4.5

v = √4.5 = 2.12m/s