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4 votes
A cake recipe contains sugar and flour in the ratio 3 : 2.

How much of each ingredient is needed to make 600 gram of such a cake?

User Maxdec
by
4.5k points

2 Answers

4 votes

Answer:

360 grams of sugar and 240 grams of flour

Explanation:

First, find the sum of the parts of the ratio: 3 + 2 = 5

Divide the total amount (600) by the amount of parts:

600/5 = 120

Now multiply 120 by the amount of each part of the ratio:

210 * 3 = 360

360 * 2 = 240

360 grams of sugar and 240 grams of flour are needed to make 600 grams of a cake.

Hope this helps :)

User Mario Murrent
by
4.9k points
0 votes

Answer:

360 g of sugar and 240 g of flour

Explanation:

add the parts of the ratio, 3 + 2 = 5 parts

Divide the total by 5 to find the value of one part of the ratio.

600 g ÷ 5 = 120 g , thus

3 parts = 3 × 120 g = 360 g ← amount of sugar required

2 parts = 2 × 120 g = 240 g ← amount of flour required

User Felix Lamouroux
by
4.7k points
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