Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.

y=-16x^2+275x+127

Answer 1

• 1308.6 feet

Explanation:

Given is the quadratic equation

• y= -16x^2 + 275x + 127

It has the maximum height at its vertex, x-coordinate of which is calculated by the formula:

• x = -b/2a
• x = -275/2(-16) = 8.6 rounded to the nearest tenths

Calculating the highest point:

• y = -16(8.6)^2 + 275(8.6) + 127 = 1308.6 feet rounded to the nearest tenths