Question

What is the molality of a solution prepared by dissolving 150.0 g C6H12O6 in 600.0 g of H2O?

Answer 1

50/36 = 25/18

Step-by-step explanation:

Solution at attachment box

Molality = mole of dissolvable (this question glucose) / kg of water

Answer 2

Molality = 1.38 mol/Kg

Step-by-step explanation:

Given data:

Molality of solution = ?

Mass of C₆H₁₂O₆ = 150.0 g

Mass of water = 600.0 g (600 g ×1 kg/1000 g= 0.6 Kg)

Solution:

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 150.0 g/180.16 g/mol

Number of moles = 0.83 mol

Molality:

Molality = moles of solute / kg of solvent

Molality = 0.83 mol /0.6 Kg

Molality = 1.38 mol/Kg