Answer:
23) +) JL ≅ MO (given)
+) KL ≅ NO (given)
+) ∠K = ∠N = 90° (given)
=> ΔJKL ≅ ΔMNO (HL)
24) +) AC ≅ EC (given)
+) BC ≅ DC (given)
+) ∠ECD = ∠ ACB (2 opposing angles)
=> ΔABC ≅ ΔEDC (SAS)
Explanation:
23.Use RHS
24.Use axiom and make 2angle equal then triangle will be equal and it becomes congruent
5.1m questions
6.7m answers