Question

Calculate the number of sulfate ions in 41.65 g of aluminum sulfate.

Answer 1

The number of sulfate ions : 2.2 x 10²³

Further explanation

Reaction

Al₂(SO₄)₃⇒2Al³⁺+3SO₄²⁻

mol Al₂(SO₄)₃(MW=342,15 g/mol) :

`\tt (41.65)/(342.15)=0.122`

mol of sulfate ions (SO₄²⁻)

`\tt 3* 0.122=0.366`

1 mol = 6.02 x 10²³ particles (ions, molecules, atoms), so for 0.366 mol :

`\tt 0.366* 6.02* 10^(23)=2.20* 10^(23)`