Answer:
Explanation:
Remark
The first step is the critical one. Take the base and raise it to x. Then take the log of the base and the number whose log you need. x (the power)is brought down and the logs divided.
2^x = 1024
log 2^x = log(1024)
x log(2) = log(1024)
x * 0.30102 = 3.0102
x = 30102/0.30102
x = 10
You could use the e system to solve this as well
2^x = 1024
ln(2^x) = ln(1024)
x * ln(2) = ln(1024)
x 0.6931 = 6.9315
x = 6.9315/0.69315
x = 9.999959
x = 10