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Calculate the ΔHrxn for the following Fe2O3(s)+3CO→Fe(s)+3CO2(g) Given: 4Fe(s)+3O2(g)→2Fe2O3(s) ΔH = -1645.36 2CO2(g)→2CO(g)+O2(g) ΔH = 567.66
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Calculate the ΔHrxn for the following

Fe2O3(s)+3CO→Fe(s)+3CO2(g)
Given:
4Fe(s)+3O2(g)→2Fe2O3(s)
ΔH = -1645.36

2CO2(g)→2CO(g)+O2(g)
ΔH = 567.66

User RedScourge
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1 Answer

3 votes

Answer: alright now listen fe203(s)=567.66666

Step-by-step explanation:

User Eli Friedman
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