Answer:
![y = -(1)/(2)x + 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/wgpt7gtoujy8ja9k9i0vcfwq3tr58i5y2h.png)
Explanation:
To create an equation in slope-intercept form, y = mx + b, for the path, we need to find slope (m) of the path, and also determine the y-intercept (b) of the path.
First, find the slope of the main street:
Using two points on the main street, (2, 3) and (3, 5),
![slope (m) = (y_2 - y_1)/(x_2 -x_1) = (5 - 3)/(3 - 2) = (2)/(1) = 2](https://img.qammunity.org/2021/formulas/mathematics/college/erw73nhcgaru81kyayoekr6pp76o59xggs.png)
Since the path would be perpendicular to the main street, therefore, the slope of the path would be the negative reciprocal of 2.
Thus, the slope of the path, m = -½.
The y-intercept of the path is the point at which the line of the path cuts across the y-axis.
The path intercepts the y-axis at y = 3. Therefore, the y-intercept (b) = 3.
Substitute m = -½, and b = 3 into
.
✅The equation that represents the path would be:
![y = -(1)/(2)x + 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/wgpt7gtoujy8ja9k9i0vcfwq3tr58i5y2h.png)