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How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the following reaction? Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3
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How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the following reaction?

Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3

User Azzy Elvul
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1 Answer

6 votes

Answer:

2.79g

Step-by-step explanation:

User Keisuke FUJII
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