How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the following reaction? Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3

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asked Jul 22, 2021 56.6k views

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How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the following reaction?

Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3

Chemistry
high-school

Azzy Elvul asked

by Azzy Elvul

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1 Answer

6 votes

Answer:

2.79g

Step-by-step explanation:

Keisuke FUJII answered Jul 28, 2021

by Keisuke FUJII

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