Answer:
50 Watts
Step-by-step explanation:
For this problem, we simply apply Ohm's law:
V = IR
V / R = I
P = IV
P = ( V / R ) V
P = ( V^2 / R )
P = (20 V)^2 / 8 Ω
P = 400 V^2 / 8 Ω
P = 50 Watts
Hence, the power consumed by the lightbulb is 50 Watts.
Cheers.