Write, in slope intercept form, the equation of the line that passes through (8, -9) and has a slope of -5/4.

Question

asked Apr 12, 2021 172k views

1 Answer

Kerem Demirer · Answer 1 · 2021-04-17T02:37:48+0000

Answer:

The equation in the slope-intercept form will be:

y=-(5)/(4)x+1

Explanation:

Given

As we know that the equation of a line in point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -5/4 and point = (8, -9)

$y-\left(-9\right)=(-5)/(4)\left(x-8\right)$

$y+9=(-5)/(4)\left(x-8\right)$

Writing the equation in slope-intercept form

y=mx+b

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

$y+9=(-5)/(4)\left(x-8\right)$

subtract 9 from both sides

$y+9-9=(-5)/(4)\left(x-8\right)-9$

y=-(5)/(4)x+1

Therefore, the equation in the slope-intercept form will be:

y=-(5)/(4)x+1