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(1)/( \sec(1 - \sin(x) ) ) dx
Any help with this? ​

(1)/( \sec(1 - \sin(x) ) ) dx Any help with this? ​-example-1
User Crashworks
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\displaystyle(1)/(\sec x(1-\sin x))=(\cos x)/(1-\sin x)\\\\\\\int (dx)/(\sec x(1-\sin x))=\int(\cos x\, dx)/(1-\sin x)\\\\\\u=1-\sin x\\du=-\cos x\, dx\\\\\int (\cos x\, dx)/(1-\sin x)=\int (-du )/(u)=-\int (du)/(u)=-\ln |u|+C=-\ln|1-\sin x|+C

User Gamlor
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