Question

Write an equation of the line with slope -5 that goes through the point (4, -7).

Group of answer choices

y = -5x + 13
y = 13x - 5
y = -5x - 7
y = -5x + 33

Answer 1

`(\stackrel{x_1}{4}~,~\stackrel{y_1}{-7})\hspace{10em} \stackrel{slope}{m} ~=~ -5 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-5}(x-\stackrel{x_1}{4}) \\\\\\ y+7=-5x+20\implies y=-5x+13`