A cylinderical container of height 28cm and diameter 18cm is filled with water. The water is then poured into another container with a rectangular base 27cm and width 11cm. Calc…

Question

asked Apr 22, 2021 184k views

1 Answer

Diaz · Answer 1 · 2021-04-29T02:58:30+0000

Answer:

h = 24 cm

Explanation:

volume of water in the cylinder = volume of water in the rectangular base container

But ,

volume of cylinder =
$\pi$
r^(2) h

where: is the radius and h is the height.

volume of cuboid = length x width x height

= l x w x h

So that;

$\pi$
r^(2) h = l x w x h

But, r =
(diameter)/(2) =
(18)/(2) = 9 cm, height of cylinder = 28 cm, length = 27 cm, width = 11 cm,
$\pi$ =
(22)/(7) .

Thus,

(22)/(7) x
(9)^(2) x 28 = 27 x 11 x h

(22)/(7) x 81 x 28 = 27 x 11 x h

7128 = 297h

h =
(7128)/(297)

= 24

h = 24 cm

The depth of the water in the container is 24 cm.