Question

A cylinderical container of height 28cm and diameter 18cm is filled with water. The water is then poured into another container with a rectangular base 27cm and width 11cm. Calculate the depth of the water in the container ( take π=22/7)

Answer 1

h = 24 cm

Explanation:

volume of water in the cylinder = volume of water in the rectangular base container

But ,

volume of cylinder =
`\pi`
`r^(2)`h

where: is the radius and h is the height.

volume of cuboid = length x width x height

= l x w x h

So that;

`\pi`
`r^(2)`h = l x w x h

But, r =
`(diameter)/(2)` =
`(18)/(2)` = 9 cm, height of cylinder = 28 cm, length = 27 cm, width = 11 cm,
`\pi` =
`(22)/(7)`.

Thus,

`(22)/(7)` x
`(9)^(2)` x 28 = 27 x 11 x h

`(22)/(7)` x 81 x 28 = 27 x 11 x h

7128 = 297h

h =
`(7128)/(297)`

= 24

h = 24 cm

The depth of the water in the container is 24 cm.