Question

Date Time Manipulation Exploration If you start from Jan 1st, 1757, and repeatedly add 8 days, until you hit 1800, how many times will it be a Monday? # YOUR CODE HERE def calcDays (): my_date = date(1757, 1, 1) m = 0 while my_date.year != 1800 : my_date = my_date + timedelta(days = 8) if my_date.isoweekday () == 1: m += 1 return m Make a function Once you have answered this question, convert your code into a generalized function. This function, call it count_weekdays should take: start_date: a start date (a datetime object) add_days : a number of days to add (an int) • stop_year: a stop year (an int) • weekday : a day to count, represented in isoweekday format (an int) It should return the number of weekday is that occur from the start date, until stop year, when adding add_days days.

Answer 1

from datetime import datetime, date, timedelta

def count_weekdays(start_date, add_days, stop_year, weekday):

my_date = start_date

m = 0

while my_date.year != stop_year:

my_date = my_date + timedelta(days = add_days)

if my_date.isoweekday() == weekday:

m += 1

return m

date_val = date(1757,1,1)

try:

date_val = datetime.fromisoformat(input("Enter date in the format yyyy-mm-dd: "))

except ValueError:

print("Wrong isoformat string")

print(count_weekdays(date_val, 8, 1800, 1))

Step-by-step explanation:

The datetime package of the python programming language has several time modules like the date, datetime, pytz, timedelta, etc, used to manipulate date and time in documents. The function count_weekdays has four parameters and returns the number of a specified weekday in a period of time.