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Carols den is 8 feet longer than it is wide. If the dens area is 209 square feet what are the dinensions of the room?

User Pzeszko
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1 Answer

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Final answer:

The width of the den is 11 feet and the length is 19 feet.

Step-by-step explanation:

Let x be the width of the den. According to the problem, the length is 8 feet longer than the width, so the length would be x + 8. The area of a rectangle is given by multiplying the length by the width, so we can set up the equation:

x(x + 8) = 209

Expanding the equation gives us a quadratic equation:

x^2 + 8x - 209 = 0

We can solve this equation by factoring or using the quadratic formula. By factoring, we find:

(x - 11)(x + 19) = 0

Setting each factor equal to zero, we find two possible values for x: x = 11 and x = -19. Since the dimensions of the den can't be negative, the width of the den is 11 feet. Therefore, the length of the den would be 11 + 8 = 19 feet.

User John Sterling
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